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DPC
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{{about|在八行全消后使用的带有一个 TSD 的六行全消定式|开局打出两个 TSD 然后六行全消的定式|DDPC}} '''DPC''' 是一类带有一个 TSD 的六行[[全消]]定式的总称,其命名中的 D 是 TSD(T-Spin Double)的缩写,PC 是全消(Perfect Clear)的缩写。 DPC 不是开局定式,需要使用前一包的1个方块与完整的两包14个方块。因此通常情况下 DPC 在完成连续两个四行 PC 或一个八行 PC 后使用。 == 总述 == === 条件与特点 === 在 [[7-Bag]] 环境中,整数包的方块被完全消除后会留下空场地与完整的下一包,与游戏开局的情形完全相同,从而可以重复执行相同的策略。这样就称为 PC 循环。因为一行是10小格,而一包7个方块有28小格相当于2.8行,容易知道在单人模式或未收到垃圾行的情况下只有 5n 包可以完全消除,实现循环。 考虑一些已有的循环方案: * 如果使用纯粹的连续四行 PC,那么需要连续7个 PC、消除10包28行,才能完成一个循环。在一个循环之内,每个 PC 都会使用下一包不同数量的方块,下一个 PC 面对的余块数量各不相同,需要使用不同的定式。因此在连续 PC 术语中,它们被依次命名为'''第 n 个 PC'''('''1st PC, 2nd PC, ... 7th PC''')。考虑到余块种类也有多种可能,每个 PC 的地基和解法数量更是成倍增加。因此,连续四行 PC 循环需要玩家记忆大量内容,只有很少的玩家能够做到,在 PC 模式之外较少被使用。 * 如果考虑其他 PC 方式,那么可以实现理论最短的循环长度,即5包14行。已经存在这个长度的开局定式,如 [[BT 炮开局]],可以自身循环。但这些定式也有得分效率可能不够高、在对战中不够灵活等缺点,一般不被认为是最优策略。 * 两行 PC 配合三个四行 PC 也可以完成最短的五包循环,而且得分效率极高。但两行 PC 的概率过低,不能成为稳定的策略,只能作为运气好时的额外惊喜。 DPC 几乎完美地解决了上述三者的问题。DPC 在完成两个四行 PC 或一个八行 PC 之后使用,消除六行,完成五包循环;一组最少的 DPC 定式可以覆盖全部的余块情况,最大限度减少了记忆量,而且几乎一定成功<ref group = "注">事实上所有情况下都有100% PC 的方案,但部分情况无法完成第一个 TSD 而只有 TSS,这时就不称为 DPC 而改称为 '''SPC''',因此说「几乎」。也存在极个别成功率不为100%的高分 DPC,玩家可以自主选择。</ref>;此外,DPC 可以得到可观的分数或攻击力奖励,从而使包含 DPC 的循环在效率上优于其他的策略。 更有利的是,2021年以来,玩家们开发和深入研究了以 [[SDPC]]、[[山岳堆叠二号]]等为代表的 SD、TD 系开局定式。这些定式的效率和成功率都很高,被认为是出色的定式。但它们完成的都是八行 PC、无法自身循环。DPC 恰好可以作为它们的接续,组成了完整的循环,从而使玩家可以重复使用这些强力定式。现在,「'''1st PC + 2nd PC + DPC'''」和「'''SDPC/TDPC + DPC'''」两种循环在限时打分和多人对战模式中都广泛得到使用,在很多领域是最优的策略。 === 分类与术语 === * '''余块分类''' 八行 PC 可能为 DPC 留下不同的余块,由此可以给 DPC 分为五类:余 O、余 SZ、余 I、余 T、余 JL。以余 O 块的情况为例,用于这种情况的一类 DPC 就称为余 O DPC,或者进一步简化为 O DPC。 '''注意''':这只是分类的名字,每一类之内还有多个不同的定式用于不同的块序和情况。 * '''定式分类''' 对于每一类余块情况,存在最少的几个 DPC 定式可以覆盖全部块序,称为最少 DPC(Minimal DPC Setup)或基础 DPC。一些其他的 DPC 定式可能拥有更高的额外 T 旋或消四 PC 概率,但对块序要求更苛刻、或者需要更多的定式才能覆盖全部块序,称为额外 DPC(Extra DPC Setup)或进阶 DPC。 * '''解法分类''' 对于每一个 DPC 定式,存在最少的几个解法可以覆盖全部块序,称为最少解(Minimal Solution)或基础解。一些其他的解法可以打出额外的 T 旋或消四,但对块序要求更苛刻,称为额外解(Extra Solution)或附加解。 === 整体评价 === 不同余块的 DPC,情况、概率、优劣各不相同。 * '''余 O:最好的情况。出现频率高,必须掌握。''' 基础 DPC 有两个,搭建和解法都非常简单好记,而且即使是基础 DPC 的得分也很高。有很多出色的进阶方案。 * '''余 SZ:次好的情况。出现频率高,必须掌握。''' 基础 DPC 三选二,其中两个的形状与 O DPC 相同,但必学的一个难度很高而且得分较低。有很多出色的进阶方案。 * '''余 I:中等的情况。出现频率较低,有些开局定式不会余 I 块。''' 基础 DPC 四选三,数量较多且解法稍难,但得分很高。有很多出色的进阶方案。 * '''余 JL:较差的情况。出现频率最低,有些开局定式不会余 J、L 块。''' 基础方案有两个且都是 SPC,解法简单但得分低。有几个出色的进阶方案,但搭建条件比较复杂。 * '''余 T:较差的情况。出现频率较低,有些开局定式不会余 T 块。''' 基础方案二选一但都是 SPC,解法简单但得分低。进阶方案极少。 == [[Image:75-.png]] 基础 DPC == 这个章节所有的定式 PC 成功率都为100%。而且只需要标准的[[超级旋转系统]]就可以100%,不需要180度旋转。 基础章节以方便初学者为主要目的,因此按最简化的块序条件分小节,提供能处理对应情况的定式。这并不代表这些定式的搭建条件严格与小节标题相同。进阶章节默认读者有能力识别块序自行选择高分定式,因此按定式分小节介绍。 在每个 DPC 定式中,搭建图的黑色块代表余块;如果有镜像两种搭建,解法以左图为例;解法图的空白左侧是基础最少解,右侧是高分附加解。 === [[Image:50-.png]] 余 O DPC === 覆盖全部块序的基础 DPC 有两个。 ==== '''O 早于 L 或 J''' ==== '''Kuruma DPC'''。 {| |- valign="bottom" |<center>O 早于 L</center> {{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | | | | | | |S| | }} {{pfrow| | | | | | | |S|S|I}} {{pfrow|L|L|L|J|J| | | |S|I}} {{pfrow|L|O|O|J|Z|Z| |B|B|I}} {{pfrow| |O|O|J| |Z|Z|B|B|I}} {{pfend}} |<center>O 早于 J</center> {{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | |Z| | | | | | | }} {{pfrow|I|Z|Z| | | | | | | }} {{pfrow|I|Z| | | |L|L|J|J|J}} {{pfrow|I|B|B| |S|S|L|O|O|J}} {{pfrow|I|B|B|S|S| |L|O|O| }} {{pfend}} |} 解法有很高的消四概率。 {| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|I|L|S|T|T|T|J|J|O|O}} {{pfrow|I|L|S|S|T|Z|J|G|O|O}} {{pfrow|I|L|L|S|Z|Z|J|G|G|G}} {{pfrow|I|G|G|G|Z|G|G|G|G|G}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|I|L|L|L|S|S|J|J|O|O}} {{pfrow|I|L|T|S|S|Z|J|G|O|O}} {{pfrow|I|T|T|T|Z|Z|J|G|G|G}} {{pfrow|I|G|G|G|Z|G|G|G|G|G}} {{pfend}} | style="width: 2em;"| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|I|Z|Z|T|T|T|S|S|O|O}} {{pfrow|I|J|Z|Z|T|S|S|G|O|O}} {{pfrow|I|J|J|J|L|L|L|G|G|G}} {{pfrow|I|G|G|G|L|G|G|G|G|G}} {{pfend}} |} ==== '''J、L 均早于 O''' ==== '''TSD DPC''',命名是因为它有很高的额外 TSD 概率。 {| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | | | | | | | |S| }} {{pfrow|I| | | | | | | |S|S}} {{pfrow|I|L|O|O|J|J| | | |S}} {{pfrow|I|L|O|O|J|Z|Z| |B|B}} {{pfrow|I|L|L| |J| |Z|Z|B|B}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| |Z| | | | | | | | }} {{pfrow|Z|Z| | | | | | | |I}} {{pfrow|Z| | | |L|L|O|O|J|I}} {{pfrow|B|B| |S|S|L|O|O|J|I}} {{pfrow|B|B|S|S| |L| |J|J|I}} {{pfend}} |} 解法有很高的额外 T 旋概率,在以 [[Jstris]] 为代表的无延迟游戏[[得分系统]]中,TSD DPC 是基础 DPC 里得分期望最高的。 {| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|I|I|I|I|T|T|T|J|J|J}} {{pfrow|Z|Z|L|L|S|T|O|O|G|J}} {{pfrow|G|Z|Z|L|S|S|O|O|G|G}} {{pfrow|G|G|G|L|G|S|G|G|G|G}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|S|Z|Z|I|I|I|I|J|J|J}} {{pfrow|S|S|Z|Z|L|L|O|O|G|J}} {{pfrow|G|S|T|T|T|L|O|O|G|G}} {{pfrow|G|G|G|T|G|L|G|G|G|G}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|O|O|L|L|S|Z|Z|J|J|J}} {{pfrow|O|O|T|L|S|S|Z|Z|G|J}} {{pfrow|G|T|T|T|I|I|I|I|G|G}} {{pfrow|G|G|G|L|G|S|G|G|G|G}} {{pfend}} | style="width: 2em;"| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|I|I|I|I|O|O|S|J|J|J}} {{pfrow|Z|Z|L|L|O|O|S|S|G|J}} {{pfrow|G|Z|Z|L|T|T|T|S|G|G}} {{pfrow|G|G|G|L|G|T|G|G|G|G}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|Z|Z|L|I|O|O|S|J|J|J}} {{pfrow|L|L|L|I|O|O|S|S|G|J}} {{pfrow|G|Z|Z|I|T|T|T|S|G|G}} {{pfrow|G|G|G|I|G|T|G|G|G|G}} {{pfend}} |} === [[Image:50-.png]] 余 SZ DPC === 覆盖全部块序的基础 DPC 有两个(三选二)。这里均以余 S 块为例,余 Z 块的情况是它的镜像。 ==== '''O 早于 S''' ==== 这种情况有两个 DPC 可以搭建,玩家可以根据需求自行选择。 两个 DPC 的形状都与余 O 块的 DPC 情况完全相同,因此解法也相同。 {| |- valign="bottom" |<center>'''[[DPC#O 早于 L 或 J|Kuruma DPC]]'''</center> {{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | | | | | | |S| | }} {{pfrow| | | | | | | |S|S|I}} {{pfrow|B|L|L|J|J| | | |S|I}} {{pfrow|B|B|L|J|Z|Z| |O|O|I}} {{pfrow| |B|L|J| |Z|Z|O|O|I}} {{pfend}} |<center>'''[[DPC#J、L 均早于 O|TSD DPC]]'''</center> {{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | | | | | | | |S| }} {{pfrow|I| | | | | | | |S|S}} {{pfrow|I|L|L|L|J|J| | | |S}} {{pfrow|I|L|B|B|J|Z|Z| |O|O}} {{pfrow|I|B|B| |J| |Z|Z|O|O}} {{pfend}} |} Kuruma DPC 侧重消四,在[[俄罗斯方块准则]]游戏中得分期望更高。TSD DPC 侧重额外 TSD,在无延迟游戏中得分期望更高。 ==== '''O 晚于 S''' ==== '''青柠 DPC'''(Lime DPC),命名是因为两个 S 块叠放形似青柠。 {{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | | |O|O| | | | | }} {{pfrow|I| | |O|O| | | | | }} {{pfrow|I| | | |S|S|Z|Z|L|L}} {{pfrow|I|J| |S|S|B|B|Z|Z|L}} {{pfrow|I|J|J|J|B|B| | | |L}} {{pfend}} 基础解最右图可以提供额外 TSD;另外也有可以提供额外 TSS 的附加解。 {| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|S|L|L|I|I|I|I|T|T|T}} {{pfrow|S|S|L|G|G|O|O|J|T|Z}} {{pfrow|G|S|L|G|G|O|O|J|Z|Z}} {{pfrow|G|G|G|G|G|G|J|J|Z|G}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|J|J|J|I|I|I|I|L|O|O}} {{pfrow|Z|Z|J|G|G|L|L|L|O|O}} {{pfrow|G|Z|Z|G|G|T|T|T|S|S}} {{pfrow|G|G|G|G|G|G|T|S|S|G}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|J|J|J|I|I|I|I|T|T|T}} {{pfrow|Z|Z|J|G|G|O|O|S|S|L}} {{pfrow|G|Z|Z|G|G|O|O|L|L|L}} {{pfrow|G|G|G|G|G|G|S|S|T|G}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|L|L|L|I|I|I|I|J|J|J}} {{pfrow|L|O|O|G|G|S|Z|Z|T|J}} {{pfrow|G|O|O|G|G|S|S|T|T|T}} {{pfrow|G|G|G|G|G|G|S|Z|Z|G}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|O|O|J|I|I|I|I|T|T|T}} {{pfrow|O|O|J|G|G|S|Z|Z|T|L}} {{pfrow|G|J|J|G|G|S|S|L|L|L}} {{pfrow|G|G|G|G|G|G|S|Z|Z|G}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|O|O|J|I|I|I|I|L|L|L}} {{pfrow|O|O|J|G|G|S|T|T|T|Z}} {{pfrow|G|J|J|G|G|S|S|T|Z|Z}} {{pfrow|G|G|G|G|G|G|S|L|Z|G}} {{pfend}} | style="width: 2em;"| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|Z|Z|L|I|I|I|I|O|O|J}} {{pfrow|L|L|L|G|G|S|T|T|T|J}} {{pfrow|G|Z|Z|G|G|S|S|T|J|J}} {{pfrow|G|G|G|G|G|G|S|O|O|G}} {{pfend}} |} 青柠 DPC「臭名昭著」,难度很高而且得分较低,应当尽量避免。 === [[Image:50-.png]] 余 I DPC === 余 I 的 DPC 定式有很多,且搭建条件复杂。至少需要三个 DPC 才能覆盖全部块序(四选三)。 ==== '''O 早于 I''' ==== '''假黄油盒子 DPC'''(Fake Butter Box DPC)或'''冰淇淋三明治 DPC'''(Ice Cream Sandwich DPC),命名都是因为形状类似。 {| |- valign="bottom" |<center>J 早于 L</center> {{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | | | | |L| | | | }} {{pfrow| | | |L|L|L| | | | }} {{pfrow|S| | | |Z|J|I|I|I|I}} {{pfrow|S|S| |Z|Z|J|J|J|O|O}} {{pfrow| |S| |Z|B|B|B|B|O|O}} {{pfend}} |<center>L 早于 J</center> {{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | | | |J| | | | | }} {{pfrow| | | | |J|J|J| | | }} {{pfrow|I|I|I|I|L|S| | | |Z}} {{pfrow|O|O|L|L|L|S|S| |Z|Z}} {{pfrow|O|O|B|B|B|B|S| |Z| }} {{pfend}} |} 解法实际上只有一个,JLO 盒子有两种情况。 {| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|I|Z|Z|T|T|T|L|O|O|J}} {{pfrow|I|S|Z|Z|T|G|L|O|O|J}} {{pfrow|I|S|S|G|G|G|L|L|J|J}} {{pfrow|I|G|S|G|G|G|G|G|G|G}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|I|Z|Z|T|T|T|J|J|L|L}} {{pfrow|I|S|Z|Z|T|G|J|O|O|L}} {{pfrow|I|S|S|G|G|G|J|O|O|L}} {{pfrow|I|G|S|G|G|G|G|G|G|G}} {{pfend}} |} ==== '''I 早于 O 早于 J 或 L''' ==== '''坏 TKI DPC'''(Bad TKI DPC),命名是因为形状与 [[DPC#TKI|TKI DPC]] 非常相似(只有一小格不同),但得分更低。 {| |- valign="bottom" |<center>O 早于 J</center> {{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | |J|J|J| | |L|S| }} {{pfrow| |Z|O|O|J| | |L|S|S}} {{pfrow|Z|Z|O|O| | | |L|L|S}} {{pfrow|Z|I|I|I|I| |B|B|B|B}} {{pfend}} |<center>O 早于 L</center> {{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| |Z|J| | |L|L|L| | }} {{pfrow|Z|Z|J| | |L|O|O|S| }} {{pfrow|Z|J|J| | | |O|O|S|S}} {{pfrow|B|B|B|B| |I|I|I|I|S}} {{pfend}} |} 解法只有一个。 {{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|I|J|J|S|S|T|Z|Z|L|L}} {{pfrow|I|J|S|S|T|T|T|Z|Z|L}} {{pfrow|I|J|G|G|G|O|O|G|G|L}} {{pfrow|I|G|G|G|G|O|O|G|G|G}} {{pfend}} ==== '''J、L 均早于 O''' ==== 这种情况有两个 DPC 可以搭建,玩家可以根据需求自行选择。 '''鹈鹕 DPC'''(Pelican DPC),命名是因为放置 S、Z 块打出凌空 TSD 的方式与[[鹈鹕]]类似。 {| |- valign="bottom" |<center>S 早于 Z</center> {{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | | | | |O|O| | |I}} {{pfrow| | | | | |O|O| | |I}} {{pfrow|S|Z|Z| | | |J|J|J|I}} {{pfrow|S|S|Z|Z| |L|L|L|J|I}} {{pfrow| |S| | | |L|B|B|B|B}} {{pfend}} |<center>Z 早于 S</center> {{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|I| | |O|O| | | | | }} {{pfrow|I| | |O|O| | | | | }} {{pfrow|I|L|L|L| | | |S|S|Z}} {{pfrow|I|L|J|J|J| |S|S|Z|Z}} {{pfrow|B|B|B|B|J| | | |Z| }} {{pfend}} |} 基础解和附加解实际上都只有一个,基础解 OSZ 组合、附加解 SZ 块的顺序有两种情况。 {| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|I|Z|Z|T|T|T|L|L|J|J}} {{pfrow|I|S|Z|Z|T|G|G|L|J|G}} {{pfrow|I|S|S|O|O|G|G|L|J|G}} {{pfrow|I|G|S|O|O|G|G|G|G|G}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|I|O|O|T|T|T|L|L|J|J}} {{pfrow|I|O|O|S|T|G|G|L|J|G}} {{pfrow|I|Z|Z|S|S|G|G|L|J|G}} {{pfrow|I|G|Z|Z|S|G|G|G|G|G}} {{pfend}} | style="width: 2em;"| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|I|O|O|L|L|L|Z|Z|S|S}} {{pfrow|I|O|O|L|J|G|G|Z|Z|G}} {{pfrow|I|T|T|T|J|G|G|S|S|G}} {{pfrow|I|G|T|J|J|G|G|G|G|G}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|I|O|O|L|L|L|Z|Z|S|S}} {{pfrow|I|O|O|L|J|G|G|S|S|G}} {{pfrow|I|T|T|T|J|G|G|Z|Z|G}} {{pfrow|I|G|T|J|J|G|G|G|G|G}} {{pfend}} |} '''Stick DPC''',以发明者 stickmancomic 的名字命名。 {| |- valign="bottom" |<center>S 早于 Z</center> {{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|I| |Z| | | | | | | }} {{pfrow|I|Z|Z| | | | | | | }} {{pfrow|I|Z|S|S| | |J|O|O| }} {{pfrow|I|S|S| | | |J|O|O|L}} {{pfrow|B|B|B|B| |J|J|L|L|L}} {{pfend}} |<center>Z 早于 S</center> {{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | | | | | | |S| |I}} {{pfrow| | | | | | | |S|S|I}} {{pfrow| |O|O|L| | |Z|Z|S|I}} {{pfrow|J|O|O|L| | | |Z|Z|I}} {{pfrow|J|J|J|L|L| |B|B|B|B}} {{pfend}} |} 附加解可以提高消四概率。 {| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|T|T|T|L|O|O|J|J|J|I}} {{pfrow|G|T|G|L|O|O|Z|Z|J|I}} {{pfrow|G|G|G|L|L|S|S|Z|Z|I}} {{pfrow|G|G|G|G|S|S|G|G|G|I}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|T|T|T|Z|Z|S|S|L|L|I}} {{pfrow|G|T|G|J|S|S|O|O|L|I}} {{pfrow|G|G|G|J|J|J|O|O|L|I}} {{pfrow|G|G|G|G|Z|Z|G|G|G|I}} {{pfend}} | style="width: 2em;"| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|T|T|T|J|J|Z|L|L|L|I}} {{pfrow|G|T|G|J|Z|Z|L|O|O|I}} {{pfrow|G|G|G|J|Z|S|S|O|O|I}} {{pfrow|G|G|G|G|S|S|G|G|G|I}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|T|T|T|O|O|J|J|S|S|I}} {{pfrow|G|T|G|O|O|J|S|S|L|I}} {{pfrow|G|G|G|Z|Z|J|L|L|L|I}} {{pfrow|G|G|G|G|Z|Z|G|G|G|I}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|T|T|T|O|O|L|L|L|J|I}} {{pfrow|G|T|G|O|O|L|S|S|J|I}} {{pfrow|G|G|G|Z|Z|S|S|J|J|I}} {{pfrow|G|G|G|G|Z|Z|G|G|G|I}} {{pfend}} |} 鹈鹕 DPC 侧重额外 TSD,在无延迟游戏中得分期望更高。Stick DPC 无需软降、侧重消四,在俄罗斯方块准则游戏中搭建速度更快,得分期望也更高。 === [[Image:50-.png]] 余 T SPC === 余 T 的情况只有 SPC,但一个 SPC 就可以覆盖全部块序。有两个方案,玩家可以根据需求自行选择。 '''Alt SPC'''。 {| |- valign="bottom" |<center>J 早于 L</center> {{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | | | | | | | | |I}} {{pfrow| | | | |L|L| | | |I}} {{pfrow| |Z|P|P|P|L|O|O| |I}} {{pfrow|Z|Z|S|S|J|L|O|O|B|I}} {{pfrow|Z|S|S|P|J|J|J|B|B|B}} {{pfend}} |<center>L 早于 J</center> {{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|I| | | | | | | | | }} {{pfrow|I| | | |J|J| | | | }} {{pfrow|I| |O|O|J|P|P|P|S| }} {{pfrow|I|B|O|O|J|L|Z|Z|S|S}} {{pfrow|B|B|B|L|L|L|P|Z|Z|S}} {{pfend}} |} 解法: {| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|I|O|O|Z|Z|T|T|T|S|S}} {{pfrow|I|O|O|L|Z|Z|T|S|S|G}} {{pfrow|I|L|L|L|G|G|J|J|J|G}} {{pfrow|I|G|G|G|G|G|G|G|J|G}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|I|J|J|Z|Z|L|L|T|T|T}} {{pfrow|I|J|O|O|Z|Z|L|S|T|G}} {{pfrow|I|J|O|O|G|G|L|S|S|G}} {{pfrow|I|G|G|G|G|G|G|G|S|G}} {{pfend}} |} '''OSZ 球 SPC'''(OSZ Ball SPC),命名是因为解法中 OSZ 块组成一个球状。可以镜像搭建,但是只需要一个朝向就可以覆盖全部块序。 {| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|I| |Z| | | | | | | }} {{pfrow|I|Z|Z| | | | | | | }} {{pfrow|I|Z|P|P|P| | |L|S| }} {{pfrow|I|B|J|J|J|O|O|L|S|S}} {{pfrow|B|B|B|P|J|O|O|L|L|S}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | | | | | | |S| |I}} {{pfrow| | | | | | | |S|S|I}} {{pfrow| |Z|J| | |P|P|P|S|I}} {{pfrow|Z|Z|J|O|O|L|L|L|B|I}} {{pfrow|Z|J|J|O|O|L|P|B|B|B}} {{pfend}} |} 解法实际上只有一个,OSZ 球的朝向有四种情况,四种都使用可以提供更高的消四概率。 {| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|T|T|T|J|J|O|O|L|L|I}} {{pfrow|G|T|G|J|S|O|O|Z|L|I}} {{pfrow|G|G|G|J|S|S|Z|Z|L|I}} {{pfrow|G|G|G|G|G|S|Z|G|G|I}} {{pfend}} | style="width: 2em;"| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|T|T|T|J|J|Z|Z|L|L|I}} {{pfrow|G|T|G|J|O|O|Z|Z|L|I}} {{pfrow|G|G|G|J|O|O|S|S|L|I}} {{pfrow|G|G|G|G|G|S|S|G|G|I}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|T|T|T|J|J|S|S|L|L|I}} {{pfrow|G|T|G|J|S|S|O|O|L|I}} {{pfrow|G|G|G|J|Z|Z|O|O|L|I}} {{pfrow|G|G|G|G|G|Z|Z|G|G|I}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|T|T|T|J|J|Z|S|L|L|I}} {{pfrow|G|T|G|J|Z|Z|S|S|L|I}} {{pfrow|G|G|G|J|Z|O|O|S|L|I}} {{pfrow|G|G|G|G|G|O|O|G|G|I}} {{pfend}} |} OSZ 球 SPC 解法可能更简单,但需要在游戏提供180度旋转的情况下才能100%搭建成功。在标准的[[超级旋转系统]]下,就要使用 Alt SPC。 === [[Image:50-.png]] 余 JL SPC === 余 J、L 的情况只有 SPC,而且需要两个 SPC 才能覆盖全部块序。这里均以余 J 块为例,余 L 块的情况是它的镜像。 ==== '''S 早于 Z''' ==== '''MKO SPC''',命名是因为消行后留下的地形与 [[MKO 堆叠]]平放 J、L、O 块相同。 {{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| |P|Z|Z| | | | | |I}} {{pfrow| |P|P|Z|Z|J| |O|O|I}} {{pfrow|L|L|L|S|S|J|B|O|O|I}} {{pfrow|L|P|S|S|J|J|B|B|B|I}} {{pfend}} 解法: {| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|I|O|O|J|L|L|L|S|S|Z}} {{pfrow|I|O|O|J|J|J|S|S|Z|Z}} {{pfrow|I|G|G|G|L|T|T|T|Z|G}} {{pfrow|I|G|G|G|G|G|T|G|G|G}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|I|O|O|S|Z|Z|J|J|J|L}} {{pfrow|I|O|O|S|S|Z|Z|L|L|L}} {{pfrow|I|G|G|G|S|T|T|T|J|G}} {{pfrow|I|G|G|G|G|G|T|G|G|G}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|I|O|O|S|L|L|T|T|T|Z}} {{pfrow|I|O|O|S|S|L|J|J|Z|Z}} {{pfrow|I|G|G|G|S|L|J|T|Z|G}} {{pfrow|I|G|G|G|G|G|J|G|G|G}} {{pfend}} |} ==== '''Z 早于 S''' ==== '''TSM SPC''',命名是因为打出的 TSS 是 Mini TSS。 {| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | | | |J| | | | | }} {{pfrow| | |S|S|J|J|J| | |I}} {{pfrow| |S|S|Z|B|P| | | |I}} {{pfrow|O|O|Z|Z|B|P|P| |L|I}} {{pfrow|O|O|Z|B|B|P|L|L|L|I}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | | | |J| | | | | }} {{pfrow| | |O|O|J|J|J| | |I}} {{pfrow| |Z|O|O|B|P| | | |I}} {{pfrow|Z|Z|S|S|B|P|P| |L|I}} {{pfrow|Z|S|S|B|B|P|L|L|L|I}} {{pfend}} |} 解法只有一个。 {{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|I|J|J|S|S|L|L|L|O|O}} {{pfrow|I|J|S|S|G|L|Z|Z|O|O}} {{pfrow|I|J|G|G|G|G|G|Z|Z|G}} {{pfrow|I|G|G|G|G|G|T|T|T|G}} {{pfrow|G|G|G|G|G|G|G|T|G|G}} {{pfend}} 另外,在标准的[[超级旋转系统]]下,T 块需要早于凌空 J 块放置,这可能导致无法打出 Mini TSS,但搭建仍然能成功;如果先放置了 J、L 块,T 块将不能旋入。如果游戏提供180度旋转,则 T 块总能旋入,Mini TSS 总能打出。 == [[Image:75-.png]] 进阶 DPC == 这个章节的定式搭建条件更苛刻,但可以获得更高的分数。除单独说明外,其他所有定式 PC 成功率都为100%。 进阶章节默认读者有能力识别块序自行选择高分定式,因此按定式分小节介绍。 在每个 DPC 定式中,搭建图的黑色块代表余块;如果有镜像两种搭建,解法以左图为例;解法图的空白左侧是基础最少解,右侧是高分附加解。 === [[Image:50-.png]] 余 O DPC === ==== '''两行 PC''' ==== 两行 PC 接四行 PC 是无延迟游戏中得分最高的六行 PC,高于所有的 DPC,一定要最先检查。 {{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|B|B|L|L|L|J|J|J|O|O}} {{pfrow|B|B|L|I|I|I|I|J|O|O}} {{pfend}} 这之后第四包会留下 TSZ 三块,情况与 7th PC 相同。搭建 7th PC 的 TSZ 地基,解法有三个。 {| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | |S|S| | | | | | }} {{pfrow| |S|S| | | | | | | }} {{pfrow| |T|Z|Z| | | | | | }} {{pfrow|T|T|T|Z|Z| | | | | }} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|J|J|G|G|S|S|I|I|I|I}} {{pfrow|J|G|G|S|S|T|T|T|L|L}} {{pfrow|J|G|G|G|Z|Z|T|O|O|L}} {{pfrow|G|G|G|G|G|Z|Z|O|O|L}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|J|J|G|G|S|S|Z|Z|L|L}} {{pfrow|J|G|G|S|S|O|O|Z|Z|L}} {{pfrow|J|G|G|G|I|I|I|I|T|L}} {{pfrow|G|G|G|G|G|O|O|T|T|T}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|J|J|G|G|S|S|T|T|T|Z}} {{pfrow|J|G|G|S|S|O|O|T|Z|Z}} {{pfrow|J|G|G|G|I|I|I|I|Z|L}} {{pfrow|G|G|G|G|G|O|O|L|L|L}} {{pfend}} |} ==== '''神''' ==== '''神 DPC'''(God DPC),命名是因为在玩家 John Beak 最初研发该定式的计算中,它在无延迟游戏中的得分期望是所有 DPC 定式里最高的<ref group = "注">不过,后来研发出的[[DPC#暂存 O|暂存 O DPC]] 被证明比它更强。</ref>。不过,余 O 版本的神 DPC 很难搭建,需要把第三包 O 块暂存到第四包 J 块之后,而且对其他块也都有块序要求。可以镜像搭建。 {| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | | | | | | | |O|O}} {{pfrow| | | | | | | | |O|O}} {{pfrow| | | | | |S| | |B|B}} {{pfrow|L| | | | |S|S| |B|B}} {{pfrow|L|Z|Z| | | |S|J|J|J}} {{pfrow|L|L|Z|Z| |I|I|I|I|J}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|O|O| | | | | | | | }} {{pfrow|O|O| | | | | | | | }} {{pfrow|B|B| | |Z| | | | | }} {{pfrow|B|B| |Z|Z| | | | |J}} {{pfrow|L|L|L|Z| | | |S|S|J}} {{pfrow|L|I|I|I|I| |S|S|J|J}} {{pfend}} |} 这一行只列出基础解,附加解有很多因此单独列出。 {| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|T|T|T|Z|Z|L|L|I|G|G}} {{pfrow|S|T|J|J|Z|Z|L|I|G|G}} {{pfrow|S|S|J|O|O|G|L|I|G|G}} {{pfrow|G|S|J|O|O|G|G|I|G|G}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|Z|Z|T|T|T|L|L|I|G|G}} {{pfrow|S|Z|Z|T|J|J|L|I|G|G}} {{pfrow|S|S|O|O|J|G|L|I|G|G}} {{pfrow|G|S|O|O|J|G|G|I|G|G}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|O|O|T|T|T|L|L|I|G|G}} {{pfrow|O|O|S|T|J|J|L|I|G|G}} {{pfrow|Z|Z|S|S|J|G|L|I|G|G}} {{pfrow|G|Z|Z|S|J|G|G|I|G|G}} {{pfend}} |} 附加解: {| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|J|J|J|Z|Z|L|L|I|G|G}} {{pfrow|O|O|J|S|Z|Z|L|I|G|G}} {{pfrow|O|O|T|S|S|G|L|I|G|G}} {{pfrow|G|T|T|T|S|G|G|I|G|G}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|Z|Z|J|J|J|L|L|I|G|G}} {{pfrow|S|Z|Z|T|T|T|L|I|G|G}} {{pfrow|S|S|O|O|T|G|L|I|G|G}} {{pfrow|G|S|O|O|J|G|G|I|G|G}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|O|O|J|J|J|L|L|I|G|G}} {{pfrow|O|O|S|T|T|T|L|I|G|G}} {{pfrow|Z|Z|S|S|T|G|L|I|G|G}} {{pfrow|G|Z|Z|S|J|G|G|I|G|G}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|J|J|J|Z|Z|L|L|I|G|G}} {{pfrow|S|T|T|T|Z|Z|L|I|G|G}} {{pfrow|S|S|T|O|O|G|L|I|G|G}} {{pfrow|G|S|J|O|O|G|G|I|G|G}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|Z|Z|J|J|J|L|L|I|G|G}} {{pfrow|O|O|S|T|T|T|L|I|G|G}} {{pfrow|O|O|S|S|T|G|L|I|G|G}} {{pfrow|G|Z|Z|S|J|G|G|I|G|G}} {{pfend}} |} {| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|J|J|J|O|O|L|L|I|G|G}} {{pfrow|S|Z|Z|T|T|T|L|I|G|G}} {{pfrow|S|S|Z|Z|T|G|L|I|G|G}} {{pfrow|G|S|J|O|O|G|G|I|G|G}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|J|J|Z|O|O|L|L|I|G|G}} {{pfrow|J|Z|Z|T|T|T|L|I|G|G}} {{pfrow|J|Z|S|S|T|G|L|I|G|G}} {{pfrow|G|S|S|O|O|G|G|I|G|G}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|L|I|I|I|I|J|J|J|G|G}} {{pfrow|L|O|O|T|T|T|S|J|G|G}} {{pfrow|L|L|Z|Z|T|G|S|S|G|G}} {{pfrow|G|O|O|Z|Z|G|G|S|G|G}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|Z|Z|L|O|O|J|J|J|G|G}} {{pfrow|L|L|L|T|T|T|S|J|G|G}} {{pfrow|I|I|I|I|T|G|S|S|G|G}} {{pfrow|G|Z|Z|O|O|G|G|G|G|G}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|I|I|I|I|L|J|J|J|G|G}} {{pfrow|S|Z|Z|T|T|T|O|O|G|G}} {{pfrow|S|S|Z|Z|T|G|O|O|G|G}} {{pfrow|G|S|L|L|L|G|G|J|G|G}} {{pfend}} |} ==== '''TKI''' ==== '''TKI DPC''',命名是因为形状与 [[TKI-3 开局]]相同。 {| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | | |J|J|J| | |O|O}} {{pfrow|L| | |Z|Z|J|S| |O|O}} {{pfrow|L| | | |Z|Z|S|S|B|B}} {{pfrow|L|L| |I|I|I|I|S|B|B}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | | |S|Z|Z| | |O|O}} {{pfrow|L| | |S|S|Z|Z| |O|O}} {{pfrow|L| | | |S|J|J|J|B|B}} {{pfrow|L|L| |I|I|I|I|J|B|B}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|O|O| | |L|L|L| | | }} {{pfrow|O|O| |Z|L|S|S| | |J}} {{pfrow|B|B|Z|Z|S|S| | | |J}} {{pfrow|B|B|Z|I|I|I|I| |J|J}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|O|O| | |S|S|Z| | | }} {{pfrow|O|O| |S|S|Z|Z| | |J}} {{pfrow|B|B|L|L|L|Z| | | |J}} {{pfrow|B|B|L|I|I|I|I| |J|J}} {{pfend}} |} 另外,O 块的位置可以换到地基 I 块对侧,这不会影响解法的本质,因此移位的版本仍然是 TKI DPC。一些余 I、余 SZ 的 DPC 尽管乍看之下可能与 TKI-3 开局并无关系,但形状与这个移位的 TKI DPC 相同或相似,因此它们的命名也与 TKI 有关。 {| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|O|O| | | |J|J|J| | }} {{pfrow|O|O|L| | |Z|Z|J|S| }} {{pfrow|B|B|L| | | |Z|Z|S|S}} {{pfrow|B|B|L|L| |I|I|I|I|S}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|O|O| | | |S|Z|Z| | }} {{pfrow|O|O|L| | |S|S|Z|Z| }} {{pfrow|B|B|L| | | |S|J|J|J}} {{pfrow|B|B|L|L| |I|I|I|I|J}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | |L|L|L| | | |O|O}} {{pfrow| |Z|L|S|S| | |J|O|O}} {{pfrow|Z|Z|S|S| | | |J|B|B}} {{pfrow|Z|I|I|I|I| |J|J|B|B}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | |S|S|Z| | | |O|O}} {{pfrow| |S|S|Z|Z| | |J|O|O}} {{pfrow|L|L|L|Z| | | |J|B|B}} {{pfrow|L|I|I|I|I| |J|J|B|B}} {{pfend}} |} 基础解一个就可以覆盖全部块序。基础解有机会消四,附加解有机会 TSD,但要注意如果无法打出 TSD 可能不如消四解。 {| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|T|T|T|Z|Z|L|L|I|O|O}} {{pfrow|S|T|J|J|Z|Z|L|I|O|O}} {{pfrow|S|S|J|G|G|G|L|I|G|G}} {{pfrow|G|S|J|G|G|G|G|I|G|G}} {{pfend}} | style="width: 2em;"| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|J|J|J|Z|Z|L|L|I|O|O}} {{pfrow|S|T|T|T|Z|Z|L|I|O|O}} {{pfrow|S|S|T|G|G|G|L|I|G|G}} {{pfrow|G|S|J|G|G|G|G|I|G|G}} {{pfend}} |} 除此之外,还可以选择有机会三连背靠背的 TSS TSS 消四解法。 {| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | | | | | | | | | }} {{pfrow| | | |J|J|J| | |O|O}} {{pfrow|L| |P|Z|Z|J|S| |O|O}} {{pfrow|L| |P|P|Z|Z|S|S|B|B}} {{pfrow|L|L|P|I|I|I|I|S|B|B}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|L|I|T|Z|Z|J|J|J|O|O}} {{pfrow|L|I|T|T|Z|Z|S|J|O|O}} {{pfrow|L|L|T|G|G|G|S|S|G|G}} {{pfrow|G|I|G|G|G|G|G|S|G|G}} {{pfrow|G|I|G|G|G|G|G|G|G|G}} {{pfend}} |} ==== '''斜 TKI''' ==== '''斜 TKI DPC'''(Slanted TKI DPC),命名是因为它是 [[DPC#TKI|TKI DPC]] 的变体,O 块位置偏移一列。 {| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | | |J|J|J| |O|O| }} {{pfrow|L| | |Z|Z|J|S|O|O| }} {{pfrow|L| | | |Z|Z|S|S|B|B}} {{pfrow|L|L| |I|I|I|I|S|B|B}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | | |S|Z|Z| |O|O| }} {{pfrow|L| | |S|S|Z|Z|O|O| }} {{pfrow|L| | | |S|J|J|J|B|B}} {{pfrow|L|L| |I|I|I|I|J|B|B}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| |O|O| |L|L|L| | | }} {{pfrow| |O|O|Z|L|S|S| | |J}} {{pfrow|B|B|Z|Z|S|S| | | |J}} {{pfrow|B|B|Z|I|I|I|I| |J|J}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| |O|O| |S|S|Z| | | }} {{pfrow| |O|O|S|S|Z|Z| | |J}} {{pfrow|B|B|L|L|L|Z| | | |J}} {{pfrow|B|B|L|I|I|I|I| |J|J}} {{pfend}} |} 基础解和第一个附加解与 TKI DPC 相同,还有两个 TSD 附加解。 {| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|T|T|T|Z|Z|L|L|O|O|I}} {{pfrow|S|T|J|J|Z|Z|L|O|O|I}} {{pfrow|S|S|J|G|G|G|L|G|G|I}} {{pfrow|G|S|J|G|G|G|G|G|G|I}} {{pfend}} | style="width: 2em;"| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|J|J|J|Z|Z|L|L|O|O|I}} {{pfrow|S|T|T|T|Z|Z|L|O|O|I}} {{pfrow|S|S|T|G|G|G|L|G|G|I}} {{pfrow|G|S|J|G|G|G|G|G|G|I}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|O|O|J|J|S|S|I|I|I|I}} {{pfrow|O|O|J|S|S|T|T|T|L|L}} {{pfrow|Z|Z|J|G|G|G|T|G|G|L}} {{pfrow|G|Z|Z|G|G|G|G|G|G|L}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|Z|Z|J|J|S|S|I|I|I|I}} {{pfrow|O|O|J|S|S|T|T|T|L|L}} {{pfrow|O|O|J|G|G|G|T|G|G|L}} {{pfrow|G|Z|Z|G|G|G|G|G|G|L}} {{pfend}} |} 斜 TKI DPC 的 T 旋附加解更多,因此在无延迟游戏中的得分期望更出色,推荐玩家在能搭建时优先选择。不过它的搭建成功率略微更低,也不能走 TSS TSS 消四路线。 ==== '''黄油盒子''' ==== '''黄油盒子 DPC'''(Butter Box DPC),命名是因为两个 O 块并排形似黄油。黄油盒子对 JLZS 块的顺序也有一定的要求,玩家需要选择合适的朝向才能搭建。 {| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|J| | | | | | | | | }} {{pfrow|J|J|J| | | | | | | }} {{pfrow|L|S| | | |Z|I|I|I|I}} {{pfrow|L|S|S| |Z|Z|O|O|B|B}} {{pfrow|L|L|S| |Z| |O|O|B|B}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | | | | | | | | |L}} {{pfrow| | | | | | | |L|L|L}} {{pfrow|I|I|I|I|S| | | |Z|J}} {{pfrow|B|B|O|O|S|S| |Z|Z|J}} {{pfrow|B|B|O|O| |S| |Z|J|J}} {{pfend}} |} 基础解有较高的消四概率,附加解还有机会做额外的 TSD。 {| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|T|T|T|S|S|I|L|O|O|J}} {{pfrow|G|T|S|S|Z|I|L|O|O|J}} {{pfrow|G|G|G|Z|Z|I|L|L|J|J}} {{pfrow|G|G|G|Z|G|I|G|G|G|G}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|T|T|T|S|S|I|J|J|L|L}} {{pfrow|G|T|S|S|Z|I|J|O|O|L}} {{pfrow|G|G|G|Z|Z|I|J|O|O|L}} {{pfrow|G|G|G|Z|G|I|G|G|G|G}} {{pfend}} | style="width: 2em;"| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|Z|Z|I|I|I|I|S|S|L|L}} {{pfrow|G|Z|Z|J|J|S|S|O|O|L}} {{pfrow|G|G|G|J|T|T|T|O|O|L}} {{pfrow|G|G|G|J|G|T|G|G|G|G}} {{pfend}} |} 此外,黄油盒子很适应 [[TETR.IO]] Blitz 模式后期的高重力。 === [[Image:50-.png]] 余 SZ DPC === 这里均以余 S 块为例,余 Z 块的情况是它的镜像。 ==== '''暂存 O''' ==== '''暂存 O DPC'''(Hold O DPC),命名是因为需要玩家把 O 块暂存到打出 TSD 之后。 {{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | |L| | | | | | | }} {{pfrow| | |L| | | | |O|O| }} {{pfrow| |Z|L|L| |S|S|O|O|J}} {{pfrow|Z|Z|B|B|S|S|T|T|T|J}} {{pfrow|Z|B|B|I|I|I|I|T|J|J}} {{pfend}} 解法: {| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|I|J|J|T|T|T|Z|Z|L|L}} {{pfrow|I|J|G|S|T|O|O|Z|Z|L}} {{pfrow|I|J|G|S|S|O|O|G|G|L}} {{pfrow|I|G|G|G|S|G|G|G|G|G}} {{pfend}} | style="width: 2em;"| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|I|J|J|O|O|S|Z|Z|L|L}} {{pfrow|I|J|G|O|O|S|S|Z|Z|L}} {{pfrow|I|J|G|T|T|T|S|G|G|L}} {{pfrow|I|G|G|G|T|G|G|G|G|G}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|L|L|L|O|O|S|I|I|I|I}} {{pfrow|L|Z|G|O|O|S|S|J|J|J}} {{pfrow|Z|Z|G|T|T|T|S|G|G|J}} {{pfrow|Z|G|G|G|T|G|G|G|G|G}} {{pfend}} |} 暂存 O DPC 的搭建率很低,但在无延迟游戏中的得分期望是所有 DPC 定式里最高的,超越了比它更早被研发出的[[DPC#神|神 DPC]]。而且它可以避开部分晚 O 块序的[[DPC#O 晚于 S|青柠 DPC]]。 ==== '''神''' ==== 余 SZ 版本的'''神 DPC'''(God DPC)。与移位的余 O 版本[[DPC#神|神 DPC]] 形状完全相同,因此解法也相同。 {{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|O|O| | | | | | | | }} {{pfrow|O|O| | | | | | | | }} {{pfrow|I|S| | | | | |B| | }} {{pfrow|I|S|S| | | | |B|B| }} {{pfrow|I|J|S|Z|Z| | | |B|L}} {{pfrow|I|J|J|J|Z|Z| |L|L|L}} {{pfend}} ==== '''TKI''' ==== 余 SZ 版本的 '''TKI DPC'''。与移位的余 O 版本 [[DPC#TKI|TKI DPC]] 形状完全相同,因此解法也相同。 {{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|Z|Z| | | |O|O|S| | }} {{pfrow|J|Z|Z| | |O|O|S|S| }} {{pfrow|J|J|J| | | |B|B|S|L}} {{pfrow|I|I|I|I| |B|B|L|L|L}} {{pfend}} ==== '''变形 TKI''' ==== '''变形 TKI DPC'''(Out of Order TKI DPC),命名是因为它在搭建上是余 SZ 版本的 [[DPC#TKI 2|TKI DPC]] 的变体,只有 Z 块的放置位置不同。 {{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | | | | |Z|Z| | | }} {{pfrow| | | | | | |Z|Z| | }} {{pfrow| | | | | |O|O|S| | }} {{pfrow|J| | | | |O|O|S|S| }} {{pfrow|J|J|J| | | |B|B|S|L}} {{pfrow|I|I|I|I| |B|B|L|L|L}} {{pfend}} 但是二者的关系仅限搭建方式部分。从形状本质来说,变形 TKI DPC 反而与[[DPC#神|神 DPC]] 完全相同: {| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | | | | |G|G|-|-|-}} {{pfrow| | | | | | |G|G|-|-}} {{pfrow| | | | | |G|G|G|-|-}} {{pfrow|G| | | | |G|G|G|G|-}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | | | | |-|-|-|G|G}} {{pfrow| | | | | | |-|-|G|G}} {{pfrow| | | | | |G|-|-|G|G}} {{pfrow|G| | | | |G|G|-|G|G}} {{pfend}} |} 从示意图可以看出,二者的留空区域是由完全相同的两部分组成的。而且根据玩家研究,这个移位不会改变解集。因此变形 TKI DPC 的解法与神 DPC 完全相同,共享相同的3个基础解和10个附加解。 不过,移位虽然不改变解的方法和数量,但会影响极个别块序可做的附加解。这导致变形 TKI DPC 的 T 旋率微弱地更高,而神 DPC 的消四率微弱地更高。 ==== '''弱变形 TKI''' ==== '''弱变形 TKI DPC''',命名是因为它是[[DPC#变形 TKI|变形 TKI DPC]] 的再变体,但附加解更少因此性能更弱。 {{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | | | | | | |O|O| }} {{pfrow| | | | | | | |O|O| }} {{pfrow| | | | | |S| |J|J| }} {{pfrow|L| | | | |S|S|J|B| }} {{pfrow|L|Z|Z| | | |S|J|B|B}} {{pfrow|L|L|Z|Z| |I|I|I|I|B}} {{pfend}} 与变形 TKI DPC 不同,弱变形 TKI DPC 不仅移位了较小的那片留空区域,还将其分割成了两块,这导致 I、L 块位置被固定。因此,它与[[DPC#神|神 DPC]] 共享相同的3个基础解和前7个附加解,但后3个附加解不可行。 {| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | | | | |G|G|-|-|-}} {{pfrow| | | | | | |G|G|-|-}} {{pfrow| | | | | |G|G|G|-|-}} {{pfrow|G| | | | |G|G|G|G|-}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | | | | |-|-|G|G|-}} {{pfrow| | | | | | |-|G|G|-}} {{pfrow| | | | | |G|-|G|G|-}} {{pfrow|G| | | | |G|G|G|G|-}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | | | | |L|L|G|G|I}} {{pfrow| | | | | | |L|G|G|I}} {{pfrow| | | | | |G|L|G|G|I}} {{pfrow|G| | | | |G|G|G|G|I}} {{pfend}} |} ==== '''大象''' ==== '''大象 DPC'''(Elephant DPC)。 {{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|I| | | | | |S|S| | }} {{pfrow|I|J|J|Z|Z|S|S| | | }} {{pfrow|I|J|O|O|Z|Z|B|B| |L}} {{pfrow|I|J|O|O| |B|B|L|L|L}} {{pfend}} 基础解: {| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|S|Z|Z|I|I|I|I|L|L|L}} {{pfrow|S|S|Z|Z|T|T|T|L|O|O}} {{pfrow|G|S|J|J|J|T|G|G|O|O}} {{pfrow|G|G|G|G|J|G|G|G|G|G}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|S|Z|Z|I|I|I|I|L|L|L}} {{pfrow|S|S|Z|Z|T|T|T|L|O|O}} {{pfrow|G|S|J|J|J|T|G|G|O|O}} {{pfrow|G|G|G|G|J|G|G|G|G|G}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|S|Z|Z|T|T|T|I|I|I|I}} {{pfrow|S|S|Z|Z|T|L|L|L|O|O}} {{pfrow|G|S|J|J|J|L|G|G|O|O}} {{pfrow|G|G|G|G|J|G|G|G|G|G}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|J|J|J|T|T|T|I|I|I|I}} {{pfrow|Z|Z|J|S|T|L|L|L|O|O}} {{pfrow|G|Z|Z|S|S|L|G|G|O|O}} {{pfrow|G|G|G|G|S|G|G|G|G|G}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|O|O|J|S|T|T|T|Z|Z|L}} {{pfrow|O|O|J|I|I|I|I|L|L|L}} {{pfrow|G|J|J|S|S|T|G|G|Z|Z}} {{pfrow|G|G|G|G|S|G|G|G|G|G}} {{pfend}} |} 附加解: {| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|O|O|I|I|I|I|L|J|J|J}} {{pfrow|O|O|S|S|L|L|L|Z|Z|J}} {{pfrow|G|S|S|T|T|T|G|G|Z|Z}} {{pfrow|G|G|G|G|T|G|G|G|G|G}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|S|I|I|I|I|O|O|J|J|J}} {{pfrow|S|S|L|L|L|O|O|Z|Z|J}} {{pfrow|G|S|L|T|T|T|G|G|Z|Z}} {{pfrow|G|G|G|G|T|G|G|G|G|G}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|Z|Z|J|J|J|O|O|S|L|L}} {{pfrow|I|I|I|I|J|O|O|S|S|L}} {{pfrow|G|Z|Z|T|T|T|G|G|S|L}} {{pfrow|G|G|G|G|T|G|G|G|G|G}} {{pfend}} |} ==== '''JB''' ==== '''JB DPC''',以发明者 John Beak 的名字命名。 {{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | | | | |S| | | | }} {{pfrow| | | | | |S|S| | |I}} {{pfrow|B|L|L| | | |S|O|O|I}} {{pfrow|B|B|L|J| |Z|Z|O|O|I}} {{pfrow| |B|L|J|J|J|Z|Z| |I}} {{pfend}} 解法实际上只有两个,3*4盒子有两种情况。 {| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|I|J|J|L|L|Z|Z|T|T|T}} {{pfrow|I|J|O|O|L|G|Z|Z|S|S}} {{pfrow|I|J|O|O|L|G|G|S|S|G}} {{pfrow|I|G|G|G|G|G|G|G|T|G}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|I|L|O|O|J|Z|Z|T|T|T}} {{pfrow|I|L|O|O|J|G|Z|Z|S|S}} {{pfrow|I|L|L|J|J|G|G|S|S|G}} {{pfrow|I|G|G|G|G|G|G|G|T|G}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|I|Z|Z|L|L|T|T|T|O|O}} {{pfrow|I|J|Z|Z|L|G|T|S|O|O}} {{pfrow|I|J|J|J|L|G|G|S|S|G}} {{pfrow|I|G|G|G|G|G|G|G|S|G}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|I|L|J|J|J|T|T|T|O|O}} {{pfrow|I|L|Z|Z|J|G|T|S|O|O}} {{pfrow|I|L|L|Z|Z|G|G|S|S|G}} {{pfrow|I|G|G|G|G|G|G|G|S|G}} {{pfend}} |} JB DPC 在无延迟游戏中的得分期望较低,唯一的优点是可以避开一部分晚 O 块序的[[DPC#O 晚于 S|青柠 DPC]]。但它有较高的消四概率,在俄罗斯方块准则游戏中是得分期望高的不错方案。 ==== '''长 S''' ==== '''长 S DPC'''(Long S DPC),命名是因为两个 S 并排放置。 {| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|J| | | | | | | | | }} {{pfrow|J|J|J| | | | | | | }} {{pfrow|O|O| | | |S|S|B|B|Z}} {{pfrow|O|O|L| |S|S|B|B|Z|Z}} {{pfrow|L|L|L| |I|I|I|I|Z| }} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|J| | | | | | | | | }} {{pfrow|J|J|J| | | | | | | }} {{pfrow|O|O| | | |Z|I|I|I|I}} {{pfrow|O|O|L| |Z|Z|S|S|B|B}} {{pfrow|L|L|L| |Z|S|S|B|B| }} {{pfend}} |} 唯一一个基础解覆盖全部块序,3*4盒子有两种情况。附加解可以进一步提高消四概率。 {| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|T|T|T|S|S|L|O|O|J|I}} {{pfrow|G|T|S|S|Z|L|O|O|J|I}} {{pfrow|G|G|G|Z|Z|L|L|J|J|I}} {{pfrow|G|G|G|Z|G|G|G|G|G|I}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|T|T|T|S|S|J|J|L|L|I}} {{pfrow|G|T|S|S|Z|J|O|O|L|I}} {{pfrow|G|G|G|Z|Z|J|O|O|L|I}} {{pfrow|G|G|G|Z|G|G|G|G|G|I}} {{pfend}} | style="width: 2em;"| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|Z|Z|T|T|T|S|S|O|O|I}} {{pfrow|G|Z|Z|T|S|S|J|O|O|I}} {{pfrow|G|G|G|L|L|L|J|J|J|I}} {{pfrow|G|G|G|L|G|G|G|G|G|I}} {{pfend}} |} 长 S DPC 没有 T 旋解,因此不适合无延迟游戏;但是有较高的消四概率,在俄罗斯方块准则游戏中是得分期望高的不错方案。 === [[Image:50-.png]] 余 I DPC === 余 I 的进阶 DPC 大多数会形成和前文已有的 DPC 相同的形状,包括暂存 O、神、TKI、变形 TKI,还有基础章节的 TSD 和 Kuruma。 ==== '''暂存 O''' ==== 余 I 版本的'''暂存 O DPC'''(Hold O DPC),命名同样是因为需要玩家把 O 块暂存到打出 TSD 之后。可以镜像搭建。 {| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | | | | | | | | |I}} {{pfrow| | | | | |O|O| | |I}} {{pfrow| |Z| |S|S|O|O|J|L|I}} {{pfrow|Z|Z|S|S|T|T|T|J|L|I}} {{pfrow|Z|B|B|B|B|T|J|J|L|L}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|I| | | | | | | | | }} {{pfrow|I| | |O|O| | | | | }} {{pfrow|I|J|L|O|O|Z|Z| |S| }} {{pfrow|I|J|L|T|T|T|Z|Z|S|S}} {{pfrow|J|J|L|L|T|B|B|B|B|S}} {{pfend}} |} 与[[DPC#弱变形 TKI|弱变形 TKI DPC]] 相似的情况:余 I 版本的暂存 O DPC 在形状本质上也是余 SZ 版本[[DPC#暂存 O|暂存 O DPC]] 的移位,但同样将较小的那片留空区域分割成了两块,这导致 I、J 块位置被固定。因此,二者共享相同的一个基础解和第一个附加解,但第二个附加解不可行。 {| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|-|-|-| | | | | | | }} {{pfrow|-|-|G| | | | | | | }} {{pfrow|-|-|G| | | | |G|G| }} {{pfrow|-|G|G|G| |G|G|G|G|G}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|-| | | | | | | |-|-}} {{pfrow|-| | | | | | | |-|G}} {{pfrow|-| | | | |G|G| |-|G}} {{pfrow|-|G| |G|G|G|G|G|G|G}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|I| | | | | | | |J|J}} {{pfrow|I| | | | | | | |J|G}} {{pfrow|I| | | | |G|G| |J|G}} {{pfrow|I|G| |G|G|G|G|G|G|G}} {{pfend}} |} ==== '''神''' ==== 余 I 版本的'''神 DPC'''(God DPC)。与余 O 版本[[DPC#神|神 DPC]] 形状完全相同,因此解法也相同。可以镜像搭建。 {| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | | | | | | | |O|O}} {{pfrow| | | | | | | | |O|O}} {{pfrow| | | | | |S| | |J|I}} {{pfrow|L| | | | |S|S| |J|I}} {{pfrow|L|Z|Z| | | |S|J|J|I}} {{pfrow|L|L|Z|Z| |B|B|B|B|I}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|O|O| | | | | | | | }} {{pfrow|O|O| | | | | | | | }} {{pfrow|I|L| | |Z| | | | | }} {{pfrow|I|L| |Z|Z| | | | |J}} {{pfrow|I|L|L|Z| | | |S|S|J}} {{pfrow|I|B|B|B|B| |S|S|J|J}} {{pfend}} |} ==== '''TKI''' ==== 余 I 版本的 '''TKI DPC'''。与移位的 [[DPC#TKI|TKI DPC]] 形状完全相同,因此解法也相同。 {| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|O|O| | | |J|J|J| | }} {{pfrow|O|O|L| | |Z|Z|J|S| }} {{pfrow|L|L|L| | | |Z|Z|S|S}} {{pfrow|I|I|I|I| |B|B|B|B|S}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|O|O| | | |S|Z|Z| | }} {{pfrow|O|O|L| | |S|S|Z|Z| }} {{pfrow|L|L|L| | | |S|J|J|J}} {{pfrow|I|I|I|I| |B|B|B|B|J}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|Z|Z| | | |L|L|L| | }} {{pfrow|J|Z|Z| | |L|O|O|S| }} {{pfrow|J|J|J| | | |O|O|S|S}} {{pfrow|I|I|I|I| |B|B|B|B|S}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | |L|L|L| | | |O|O}} {{pfrow| |Z|L|S|S| | |J|O|O}} {{pfrow|Z|Z|S|S| | | |J|J|J}} {{pfrow|Z|B|B|B|B| |I|I|I|I}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | |S|S|Z| | | |O|O}} {{pfrow| |S|S|Z|Z| | |J|O|O}} {{pfrow|L|L|L|Z| | | |J|J|J}} {{pfrow|L|B|B|B|B| |I|I|I|I}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | |J|J|J| | | |S|S}} {{pfrow| |Z|O|O|J| | |S|S|L}} {{pfrow|Z|Z|O|O| | | |L|L|L}} {{pfrow|Z|B|B|B|B| |I|I|I|I}} {{pfend}} |} ==== '''变形 TKI''' ==== 余 I 版本的'''变形 TKI DPC'''(Out of Order TKI DPC)。与余 SZ 版本的[[DPC#变形 TKI|变形 TKI DPC]] 形状完全相同,从而在本质上与[[DPC#神|神 DPC]] 完全相同,从而解法也完全相同,共享相同的3个基础解和10个附加解。可以镜像搭建。 {| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | | | | |Z|Z| | | }} {{pfrow| | | | | | |Z|Z| | }} {{pfrow| | | | | |L|L|L| | }} {{pfrow|J| | | | |L|O|O|S| }} {{pfrow|J|J|J| | | |O|O|S|S}} {{pfrow|I|I|I|I| |B|B|B|B|S}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | | |S|S| | | | | }} {{pfrow| | |S|S| | | | | | }} {{pfrow| | |J|J|J| | | | | }} {{pfrow| |Z|O|O|J| | | | |L}} {{pfrow|Z|Z|O|O| | | |L|L|L}} {{pfrow|Z|B|B|B|B| |I|I|I|I}} {{pfend}} |} ==== '''高概率 TSD''' ==== 暂无命名的 DPC,特征是有高概率得到额外的 TSD。可以镜像搭建。 {| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | | | | | |J| | | }} {{pfrow| | | | | |S|J|J|J|I}} {{pfrow|L| | | | |S|S|O|O|I}} {{pfrow|L|Z|Z| | | |S|O|O|I}} {{pfrow|L|L|Z|Z| |B|B|B|B|I}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | | |L| | | | | | }} {{pfrow|I|L|L|L|Z| | | | | }} {{pfrow|I|O|O|Z|Z| | | | |J}} {{pfrow|I|O|O|Z| | | |S|S|J}} {{pfrow|I|B|B|B|B| |S|S|J|J}} {{pfend}} |} 该 DPC 的情况与[[DPC#弱变形 TKI|弱变形 TKI DPC]] 非常相似:在如图放置 I、L 块后形状又双叒叕与[[DPC#神|神 DPC]] 相同,从而共享相同的3个基础解和前7个附加解。此外,它还有第8个 TSD 附加解,解法本质与神 DPC 的第10个附加解相同。 {| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | | | | |I|I|I|I|L}} {{pfrow| | | | | | |G|L|L|L}} {{pfrow| | | | | |G|G|G|G|G}} {{pfrow|G| | | | |G|G|G|G|G}} {{pfend}} | style="width: 2em;"| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|I|I|I|I|L|J|J|J|O|O}} {{pfrow|S|Z|Z|T|T|T|G|J|O|O}} {{pfrow|S|S|Z|Z|T|G|G|G|G|G}} {{pfrow|G|S|L|L|L|G|G|G|G|G}} {{pfend}} |} ==== '''TSD''' ==== 余 I 版本的 '''TSD DPC'''。与基础章节余 O、S、Z 的 [[DPC#J、L 均早于 O|TSD DPC]] 形状完全相同,因此解法也相同。可以镜像搭建。 {| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | | | | | | | |S| }} {{pfrow|B| | | | | | | |S|S}} {{pfrow|B|L|I|I|I|I| | | |S}} {{pfrow|B|L|J|J|J|Z|Z| |O|O}} {{pfrow|B|L|L| |J| |Z|Z|O|O}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| |Z| | | | | | | | }} {{pfrow|Z|Z| | | | | | | |B}} {{pfrow|Z| | | |I|I|I|I|J|B}} {{pfrow|O|O| |S|S|L|L|L|J|B}} {{pfrow|O|O|S|S| |L| |J|J|B}} {{pfend}} |} ==== '''Kuruma''' ==== 余 I 版本的 '''Kuruma DPC'''。与基础章节余 O、S、Z 的 [[DPC#O 早于 L 或 J|Kuruma DPC]] 形状完全相同,因此解法也相同。可以镜像搭建。 {| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | |Z| | | | | | | }} {{pfrow|B|Z|Z| | | | | | | }} {{pfrow|B|Z| | | |I|I|I|I|L}} {{pfrow|B|O|O| |S|S|J|L|L|L}} {{pfrow|B|O|O|S|S| |J|J|J| }} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | | | | | | |S| | }} {{pfrow| | | | | | | |S|S|B}} {{pfrow|J|I|I|I|I| | | |S|B}} {{pfrow|J|J|J|L|Z|Z| |O|O|B}} {{pfrow| |L|L|L| |Z|Z|O|O|B}} {{pfend}} |} === [[Image:50-.png]] 余 T DPC 与 SPC === ==== '''倒置 T''' ==== '''倒置 T SPC'''(Upside-down T SPC),命名是因为余 T 块倒扣。可以镜像搭建。'''这个 SPC 的 PC 率为 99.84%'''。 {| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | | | | |L| | | | }} {{pfrow| | | | | |L| | | | }} {{pfrow|I| | |Z|Z|L|L| | | }} {{pfrow|I| | | |Z|Z| | | | }} {{pfrow|I|J| |B|B|B|S|S|O|O}} {{pfrow|I|J|J|J|B|S|S| |O|O}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | | | |J| | | | | }} {{pfrow| | | | |J| | | | | }} {{pfrow| | | |J|J|S|S| | |I}} {{pfrow| | | | |S|S| | | |I}} {{pfrow|O|O|Z|Z|B|B|B| |L|I}} {{pfrow|O|O| |Z|Z|B|L|L|L|I}} {{pfend}} |} 基础解有五个,难度较高。 {| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|O|O|J|J|J|G|I|I|I|I}} {{pfrow|O|O|S|S|J|G|Z|Z|L|L}} {{pfrow|G|S|S|G|G|G|G|Z|Z|L}} {{pfrow|G|G|G|G|G|G|T|T|T|L}} {{pfrow|G|G|G|G|G|G|G|T|G|G}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|J|J|J|O|O|G|S|L|L|I}} {{pfrow|Z|Z|J|O|O|G|S|S|L|I}} {{pfrow|G|Z|Z|G|G|G|G|S|L|I}} {{pfrow|G|G|G|G|G|G|T|T|T|I}} {{pfrow|G|G|G|G|G|G|G|T|G|G}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|O|O|J|J|J|G|Z|Z|L|I}} {{pfrow|O|O|S|S|J|G|L|L|L|I}} {{pfrow|G|S|S|G|G|G|G|Z|Z|I}} {{pfrow|G|G|G|G|G|G|T|T|T|I}} {{pfrow|G|G|G|G|G|G|G|T|G|G}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|I|I|I|I|L|G|S|J|J|J}} {{pfrow|Z|Z|L|L|L|G|S|S|O|O}} {{pfrow|G|Z|Z|G|G|G|G|S|O|O}} {{pfrow|G|G|G|G|G|G|T|T|T|J}} {{pfrow|G|G|G|G|G|G|G|T|G|G}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|Z|Z|J|J|J|G|O|O|S|S}} {{pfrow|I|I|I|I|J|G|O|O|L|L}} {{pfrow|G|Z|Z|G|G|G|G|S|S|L}} {{pfrow|G|G|G|G|G|G|T|T|T|L}} {{pfrow|G|G|G|G|G|G|G|T|G|G}} {{pfend}} | style="width: 2em;"| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|S|L|L|O|O|G|J|J|J|I}} {{pfrow|S|S|L|O|O|G|Z|Z|J|I}} {{pfrow|G|S|L|G|G|G|G|Z|Z|I}} {{pfrow|G|G|G|G|G|G|T|T|T|I}} {{pfrow|G|G|G|G|G|G|G|T|G|G}} {{pfend}} |} 虽然难解而且有小概率失败,但倒置 T SPC 的得分期望是余 T 块所有方案中最高的。 ==== '''MKO''' ==== 余 T 版本的 '''MKO DPC''',与基础章节余 JL 的 [[DPC##S 早于 Z|MKO DPC]] 形状本质相同,因此解法也相同。可以镜像搭建。 {| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| |Z| | | | | |L|L|I}} {{pfrow|Z|Z|O|O|S| | | |L|I}} {{pfrow|Z|J|O|O|S|S| |B|L|I}} {{pfrow| |J|J|J| |S|B|B|B|I}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| |Z| | | | | |J|J|J}} {{pfrow|Z|Z|L|L|S| | | |B|J}} {{pfrow|Z|O|O|L|S|S| |B|B|B}} {{pfrow| |O|O|L| |S|I|I|I|I}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|I|J|J| | | | | |S| }} {{pfrow|I|J| | | |Z|O|O|S|S}} {{pfrow|I|J|B| |Z|Z|O|O|L|S}} {{pfrow|I|B|B|B|Z| |L|L|L| }} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|L|L|L| | | | | |S| }} {{pfrow|L|B| | | |Z|J|J|S|S}} {{pfrow|B|B|B| |Z|Z|J|O|O|S}} {{pfrow|I|I|I|I|Z| |J|O|O| }} {{pfend}} |} 早 J 块、早 L 块或早 O、I 块就可以搭建。余 T 块唯一值得推荐的 DPC 方案。 === [[Image:50-.png]] 余 JL DPC === 这里均以余 J 块为例,余 L 块的情况是它的镜像。 ==== '''傀儡''' ==== '''傀儡 DPC'''(Stooge DPC)。有三种搭建方式,形成两种形状,但可以认为是相同形状的移位,解法也相同。 {| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | | | | | |J| | | }} {{pfrow| | |Z| | | |J|O|O| }} {{pfrow| |Z|Z| | |J|J|O|O|L}} {{pfrow|B|Z| | | |S|S|L|L|L}} {{pfrow|B|B|B| |S|S|I|I|I|I}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | | | | | |J| | | }} {{pfrow| | |Z| | | |J|J|J| }} {{pfrow| |Z|Z| | |O|O|S|L|L}} {{pfrow|B|Z| | | |O|O|S|S|L}} {{pfrow|B|B|B| |I|I|I|I|S|L}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| |J| | | | | | | | }} {{pfrow| |J|J|J| | |Z| | | }} {{pfrow| |S|S|O|O|Z|Z| | |B}} {{pfrow|S|S|L|O|O|Z| | | |B}} {{pfrow|L|L|L|I|I|I|I| |B|B}} {{pfend}} |} 虽然地形有两种,但基础解实际上只有一个,附加解有两个。基础解将两种地形都列出以示它们本质相同,附加解只展示一种地形。除了提高消四概率外,还有机会 TSS。 {| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|I|J|J|T|O|O|Z|Z|L|L}} {{pfrow|I|J|T|T|O|O|G|Z|Z|L}} {{pfrow|I|J|G|T|S|S|G|G|G|L}} {{pfrow|I|G|G|S|S|G|G|G|G|G}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|I|Z|Z|L|L|J|J|T|O|O}} {{pfrow|I|G|Z|Z|L|J|T|T|O|O}} {{pfrow|I|G|G|G|L|J|G|T|S|S}} {{pfrow|I|G|G|G|G|G|G|S|S|G}} {{pfend}} | style="width: 2em;"| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|I|J|J|S|S|T|Z|Z|L|L}} {{pfrow|I|J|S|S|T|T|G|Z|Z|L}} {{pfrow|I|J|G|O|O|T|G|G|G|L}} {{pfrow|I|G|G|O|O|G|G|G|G|G}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|L|L|L|T|O|O|I|I|I|I}} {{pfrow|L|Z|T|T|O|O|G|J|J|J}} {{pfrow|Z|Z|G|T|S|S|G|G|G|J}} {{pfrow|Z|G|G|S|S|G|G|G|G|G}} {{pfend}} |} ==== '''吊桥''' ==== '''吊桥 DPC'''(Drawbridge DPC)。有四种搭建方式,形成三种形状,但可以认为是相同形状的移位,解法也相同。其中两个搭建分别需要暂存 O 块 和 J 块到 TSD 之后。 {| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| |S|S| | | | | |L|L}} {{pfrow|S|S| | | |I|I|I|I|L}} {{pfrow|O|O|B| |J|J|J|Z|Z|L}} {{pfrow|O|O|B|B|B| |J| |Z|Z}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|O|O| |J|J| | | | | }} {{pfrow|O|O|L|J| | | |S|S|Z}} {{pfrow|L|L|L|J|B| |S|S|Z|Z}} {{pfrow|I|I|I|I|B|B|B| |Z| }} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| |O|O| | | | | |J|J}} {{pfrow|L|O|O|Z|Z| |S| |J|B}} {{pfrow|L|T|T|T|Z|Z|S|S|J|B}} {{pfrow|L|L|T|I|I|I|I|S|B|B}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | |Z|J| | | | |L|L}} {{pfrow| |Z|Z|J|J|J| |O|O|L}} {{pfrow|B|Z|T|T|T|S|S|O|O|L}} {{pfrow|B|B|B|T|S|S|I|I|I|I}} {{pfend}} |} 解法实际上只有一个,这里将三种地形都列出以示它们本质相同。 {| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|J|J|S|S|Z|L|L|I|O|O}} {{pfrow|J|S|S|Z|Z|T|L|I|O|O}} {{pfrow|J|G|G|Z|T|T|L|I|G|G}} {{pfrow|G|G|G|G|G|T|G|I|G|G}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|O|O|J|J|S|S|Z|L|L|I}} {{pfrow|O|O|J|S|S|Z|Z|T|L|I}} {{pfrow|G|G|J|G|G|Z|T|T|L|I}} {{pfrow|G|G|G|G|G|G|G|T|G|I}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|I|J|J|S|S|Z|L|L|O|O}} {{pfrow|I|J|S|S|Z|Z|T|L|O|O}} {{pfrow|I|J|G|G|Z|T|T|L|G|G}} {{pfrow|I|G|G|G|G|G|T|G|G|G}} {{pfend}} |} Drawbridge DPC 解法非常简单,得分期望也不错。但是,识别四种搭建方式的块序要求可能过于复杂。它们合计提供了超过50%的成功率。 ==== '''城堡塔''' ==== '''城堡塔 DPC'''(Castle Tower DPC),命名是因为只看一个 J 块时形状与 [[TKI-3 开局]]城堡型相同,而两个 J 块就把城墙升级成了高塔。 {| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | | | | | | | |O|O}} {{pfrow| | | | | | | | |O|O}} {{pfrow| | | | | | | | |J|J}} {{pfrow|L| | |Z|Z| |S| |J|B}} {{pfrow|L| | | |Z|Z|S|S|J|B}} {{pfrow|L|L| |I|I|I|I|S|B|B}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | | | | | | | |J|J}} {{pfrow| | | | | | | | |J|B}} {{pfrow| | | | | | | | |J|B}} {{pfrow|L| | |Z|Z| |S| |B|B}} {{pfrow|L| | | |Z|Z|S|S|O|O}} {{pfrow|L|L| |I|I|I|I|S|O|O}} {{pfend}} |} 基础解有三个,但其中两个没有额外 T 旋或消四可能,得分较低。 {| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|J|J|S|S|Z|L|L|I|G|G}} {{pfrow|J|S|S|Z|Z|T|L|I|G|G}} {{pfrow|J|O|O|Z|T|T|L|I|G|G}} {{pfrow|G|O|O|G|G|T|G|I|G|G}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|L|O|O|J|J|J|T|I|G|G}} {{pfrow|L|O|O|Z|Z|T|T|I|G|G}} {{pfrow|L|L|S|S|Z|Z|T|I|G|G}} {{pfrow|G|S|S|G|G|J|G|I|G|G}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|J|J|T|O|O|S|S|I|G|G}} {{pfrow|J|L|T|T|S|S|Z|I|G|G}} {{pfrow|J|L|T|O|O|Z|Z|I|G|G}} {{pfrow|G|L|L|G|G|Z|G|I|G|G}} {{pfend}} | style="width: 2em;"| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|J|J|Z|O|O|L|L|I|G|G}} {{pfrow|J|Z|Z|O|O|T|L|I|G|G}} {{pfrow|J|Z|S|S|T|T|L|I|G|G}} {{pfrow|G|S|S|G|G|T|G|I|G|G}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|O|O|L|S|J|J|J|I|G|G}} {{pfrow|O|O|L|S|S|T|J|I|G|G}} {{pfrow|Z|Z|L|L|S|T|T|I|G|G}} {{pfrow|G|Z|Z|G|G|T|G|I|G|G}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|J|J|Z|O|O|T|L|L|G|G}} {{pfrow|J|Z|Z|O|O|T|T|L|G|G}} {{pfrow|J|Z|S|S|I|I|I|I|G|G}} {{pfrow|G|S|S|G|G|T|G|L|G|G}} {{pfend}} |} ==== '''其他''' ==== * 蓝色黄油 DPC(Blue Butter DPC) - 简单但分数较低。 * STSD DPC - 余 JL 所有方案中得分期望最高,但非常难记(7+6个解),PC 率 99.72%。 <!-- == [[Image:75-.png]] 消四 DPC == 我觉得我们完全可以通过添加每个 DPC 的消四率 & T 旋率来完成同样的工作,也可以考虑增加一个大的表格来作为整个条目的整理总结。似乎没有必要单独再开第三章节来把前面讲过的 DPC 抽出几个再讲一下,这有点奇怪。 [[Image:50-.png]]<big>'''首先将 O-DPC 的搭建概率最大化'''</big> 该 DPC 的消四概率超过 80% ,是已知 DPC 中概率最高的。 {| |- valign="bottom" |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | | | | | | |S| | }} {{pfrow| | | | | | | |S|S|I}} {{pfrow|L|L|L|J|J| | | |S|I}} {{pfrow|L|B|B|J|Z|Z| |O|O|I}} {{pfrow| |B|B|J| |Z|Z|O|O|I}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | |Z| | | | | | | }} {{pfrow|I|Z|Z| | | | | | | }} {{pfrow|I|Z| | | |L|L|J|J|J}} {{pfrow|I|O|O| |S|S|L|B|B|J}} {{pfrow|I|O|O|S|S| |L|B|B| }} {{pfend}} |} 当 JL 均早于 O 时,按常规思路我们无法搭建,但是将第一个 O 的位置进行交换, 当 S (镜像为 Z )晚于 O 时,我们也可以搭建这个 DPC 。<br> 再考虑暂存 ,搭建率接近 85%! 当解法一不成立时,有一个互补型如下 {| |- valign="bottom" |<center>'''S 先 Z 后'''</center> {{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | | | |Z| | | | | }} {{pfrow|I| | |Z|Z| | | | | }} {{pfrow|I|O|O|Z| | | |J|J|J}} {{pfrow|I|O|O|S|S| |L|B|B|J}} {{pfrow|I| |S|S|L|L|L|B|B| }} {{pfend}} |<center>'''Z 先 S 后'''</center> {{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | | | | |S| | | | }} {{pfrow| | | | | |S|S| | |I}} {{pfrow|L|L|L| | | |S|O|O|I}} {{pfrow|L|B|B|J| |Z|Z|O|O|I}} {{pfrow| |B|B|J|J|J|Z|Z| |I}} {{pfend}} |} 以 S 先为例,左二为最少解,右二为消四解。 {| |- valign="bottom" |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|T|T|T|S|S|L|O|O|J|I}} {{pfrow|Z|Z|S|S|G|L|O|O|J|I}} {{pfrow|G|Z|Z|G|G|L|L|J|J|I}} {{pfrow|G|T|G|G|G|G|G|G|G|I}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|T|T|T|S|S|J|J|L|L|I}} {{pfrow|Z|Z|S|S|G|J|O|O|L|I}} {{pfrow|G|Z|Z|G|G|J|O|O|L|I}} {{pfrow|G|T|G|G|G|G|G|G|G|I}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|O|O|T|T|T|L|L|L|J|I}} {{pfrow|O|O|Z|T|G|L|S|S|J|I}} {{pfrow|G|Z|Z|G|G|S|S|J|J|I}} {{pfrow|G|Z|G|G|G|G|G|G|G|I}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|O|O|T|T|T|J|J|S|S|I}} {{pfrow|O|O|Z|T|G|J|S|S|L|I}} {{pfrow|G|Z|Z|G|G|J|L|L|L|I}} {{pfrow|G|Z|G|G|G|G|G|G|G|I}} {{pfend}} |} [[Image:50-.png]] <big>'''O-DPC 解法二成立时,可留意黄油盒子的变化形'''</big> {| |- valign="bottom" |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|J| | | | | | | | | }} {{pfrow|J|J|J| | | | | | | }} {{pfrow|L|S| | | |I|I|I|I|Z}} {{pfrow|L|S|S| |O|O|B|B|Z|Z}} {{pfrow|L|L|S| |O|O|B|B|Z| }} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|J| | | | | | | | | }} {{pfrow|J|J|J| | | | | | | }} {{pfrow|L|S| | | |Z|O|O|O|O}} {{pfrow|L|S|S| |Z|Z|O|O|O|O}} {{pfrow|L|L|S| |Z|I|I|I|I| }} {{pfend}} | style="width: 2em;"| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|T|T|T|S|S|J|J|L|L|I}} {{pfrow|G|T|S|S|Z|J|O|O|L|I}} {{pfrow|G|G|G|Z|Z|J|O|O|L|I}} {{pfrow|G|G|G|Z|G|G|G|G|G|I}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|T|T|T|S|S|L|O|O|J|I}} {{pfrow|G|T|S|S|Z|L|O|O|J|I}} {{pfrow|G|G|G|Z|Z|L|L|J|J|I}} {{pfrow|G|G|G|Z|G|G|G|G|G|I}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|Z|Z|T|T|T|S|S|O|O|I}} {{pfrow|G|Z|Z|T|S|S|J|O|O|I}} {{pfrow|G|G|G|L|L|L|J|J|J|I}} {{pfrow|G|G|G|L|G|G|G|G|G|I}} {{pfend}} |} 条件是 Z 先 I 后(或 I 抢先垫底)且 L 早,还可留意镜像形。<br> 最后一包类似黄油盒子瞄消四,方案三以失去 DDPC 为代价向 D4PC 专精。<br> [[Image:50-.png]] <big>'''S 的消四 DPC 是学习价值最高的'''</big> {| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|J| | | | | | | | | }} {{pfrow|J|J|J| | | | | | | }} {{pfrow|O|O| | | |Z|I|I|I|I}} {{pfrow|O|O|L| |Z|Z|S|S|B|B}} {{pfrow|L|L|L| |Z|S|S|B|B| }} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|J| | | | | | | | | }} {{pfrow|J|J|J| | | | | | | }} {{pfrow|O|O| | | |B|B|S|S|Z}} {{pfrow|O|O|L| |B|B|S|S|Z|Z}} {{pfrow|L|L|L| |I|I|I|I|Z| }} {{pfend}} |} 长 S 型 DPC ,整体和黄油盒子的变化形完全相同。<br> 该方案 JOL 部分可以变形: {| |- valign="bottom" |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | |L| | | | | | | }} {{pfrow|L|L|L| | | | | | | }} {{pfrow|J|J| | | |Z|I|I|I|I}} {{pfrow|J|O|O| |Z|Z|S|S|B|B}} {{pfrow|J|O|O| |Z|S|S|B|B| }} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | |L| | | | | | | }} {{pfrow|L|L|L| | | | | | | }} {{pfrow|J|J| | | |B|B|S|S|Z}} {{pfrow|J|O|O| |B|B|S|S|Z|Z}} {{pfrow|J|O|O| |I|I|I|I|Z| }} {{pfend}} | style="width: 2em;"| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|O|O|T|T|T|J|J|S|S|I}} {{pfrow|O|O|G|T|Z|J|S|S|L|I}} {{pfrow|G|G|G|Z|Z|J|L|L|L|I}} {{pfrow|G|G|G|Z|G|G|G|G|G|I}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|O|O|T|T|T|L|L|L|J|I}} {{pfrow|O|O|G|T|Z|L|S|S|J|I}} {{pfrow|G|G|G|Z|Z|S|S|J|J|I}} {{pfrow|G|G|G|Z|G|G|G|G|G|I}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|O|O|T|T|T|S|S|Z|J|I}} {{pfrow|O|O|G|T|S|S|Z|Z|J|I}} {{pfrow|G|G|G|L|L|L|Z|J|J|I}} {{pfrow|G|G|G|L|G|G|G|G|G|I}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|O|O| | |P|Z|Z|J|J|J}} {{pfrow|O|O|G|P|P|P|Z|Z|S|J}} {{pfrow|G|G|G| |I|I|I|I|S|S}} {{pfrow|G|G|G| |G|G|G|G|G|S}} {{pfend}} |} 双心型 DPC ,第一个 S 随着 I 的块序选择放在不同的黑色位置<br> 最后一包的前三种方案能覆盖多数块序,ITS 集体早出,使用最后方案妥协 PC。<br> 另外, 当 Z 早于 SO 时,S-DPC 有和 O-DPC 妥协型相同的方案,解法参考前文。 {{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | | | | |S| | | | }} {{pfrow| | | | | |S|S| | |I}} {{pfrow|B|L|L| | | |S|O|O|I}} {{pfrow|B|B|L|J| |Z|Z|O|O|I}} {{pfrow| |B|L|J|J|J|Z|Z| |I}} {{pfend}} 如果 J 和 I 来的都很早,可以搭建低配黄油盒子。 {{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | | | | |L| | | | }} {{pfrow| | | |L|L|L| | | | }} {{pfrow|S| | | |Z|J|J|J|O|O}} {{pfrow|S|S| |Z|Z|B|B|J|O|O}} {{pfrow| |S| |Z|B|B|I|I|I|I}} {{pfend}} 解法如下 {| |- valign="bottom" |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|I|Z|Z|T|T|T|L|O|O|J}} {{pfrow|I|S|Z|Z|T|G|L|O|O|J}} {{pfrow|I|S|S|G|G|G|L|L|J|J}} {{pfrow|I|G|S|G|G|G|G|G|G|G}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|I|Z|Z|T|T|T|J|J|L|L}} {{pfrow|I|S|Z|Z|T|G|J|O|O|L}} {{pfrow|I|S|S|G|G|G|J|O|O|L}} {{pfrow|I|G|S|G|G|G|G|G|G|G}} {{pfend}} |} '''S 旋型 DPC''' {| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|I| |Z| | | | | | | }} {{pfrow|I|Z|Z| | | | | | | }} {{pfrow|I|Z| | | |S|S|J|J|J}} {{pfrow|I|B|B| |S|S|L|O|O|J}} {{pfrow|B|B| | |L|L|L|O|O| }} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|I| |Z| | | | | | | }} {{pfrow|I|Z|Z| | | | | | | }} {{pfrow|I|Z| | | |O|O|L|L|L}} {{pfrow|I|B|B| |J|O|O|L|S|S}} {{pfrow|B|B| | |J|J|J|S|S| }} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|I| |Z| | | | | | | }} {{pfrow|I|Z|Z| | | | | | | }} {{pfrow|I|Z| | | |O|O|L|L|L}} {{pfrow|I|S|S| |J|O|O|L|B|B}} {{pfrow|S|S| | |J|J|J|B|B| }} {{pfend}} |} 这是一个简易的消四 DPC ,当你不想使用标准的青柠 DPC 时可以选择。 {| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|T|T|T|S|S|L|J|J|J|I}} {{pfrow|G|T|G|O|O|L|Z|Z|J|I}} {{pfrow|G|G|G|O|O|L|L|Z|Z|I}} {{pfrow|G|G|S|S|G|G|G|G|G|I}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|T|T|T|S|S|Z|Z|L|L|I}} {{pfrow|G|T|G|O|O|J|Z|Z|L|I}} {{pfrow|G|G|G|O|O|J|J|J|L|I}} {{pfrow|G|G|S|S|G|G|G|G|G|I}} {{pfend}} | style="width: 2em;"| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|T|T|T|O|O|Z|Z|L|L|I}} {{pfrow|G|T|G|O|O|J|Z|Z|L|I}} {{pfrow|G|G|G|S|S|J|J|J|L|I}} {{pfrow|G|G|S|S|G|G|G|G|G|I}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow|T|T|T|O|O|L|J|J|J|I}} {{pfrow|G|T|G|O|O|L|Z|Z|J|I}} {{pfrow|G|G|G|S|S|L|L|Z|Z|I}} {{pfrow|G|G|S|S|G|G|G|G|G|I}} {{pfend}} |} 前两者为最少解,但四个解的形式都十分简单。 [[Image:50-.png]] <big>'''I-DPC 可留意“L—S”和“J—Z”'''</big> {| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | | | | | | |S| | }} {{pfrow| | | | | | | |S|S|B}} {{pfrow|J|I|I|I|I| | | |S|B}} {{pfrow|J|J|J|L|Z|Z| |O|O|B}} {{pfrow| |L|L|L| |Z|Z|O|O|B}} {{pfend}} |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | |Z| | | | | | | }} {{pfrow|B|Z|Z| | | | | | | }} {{pfrow|B|Z| | | |I|I|I|I|L}} {{pfrow|B|O|O| |S|S|J|L|L|L}} {{pfrow|B|O|O|S|S| |J|J|J| }} {{pfend}} |} 条件一:L 早,O 先 S 后。<br> 条件二:J 早,O 先 Z 后。<br> 目标形状和 O-DPC 解法一完全相同,一旦识破,后续 D4PC 成功率高。 [[Image:50-.png]] <big>'''T-DPC 不存在 D4PC 方案'''</big><br> {| class="mw-collapsible mw-collapsed" border="2" cellpadding="2" cellspacing="0" style="margin-top:1em; margin-bottom:1em; background:#f9f9f9; border:2px #999999 solid; border-collapse:collapse;" |- align="center" | <span style="line-height: 1.8em;"> 证明过程 </span> |- | <div style="padding:0 0.4em;"> 先证明普通 T2 不行。<br> 由[[奇偶性]]原理可知,T-DPC 一旦用前八块做了普通的 T2,剩下的场地的奇偶格数之差就一定是 0 或 4。<br> 最后一包的不消行的 T 会使这个差值产生 2 的变化,最终差值必是 2 或 6,而 D4PC 需要差值是 0,所以肯定办不到。<br> <div style = "float:right;"> {| |{{pfstart}} {{pfrow| | | | | | | | | | }} {{pfrow| | | |L|L| | | | | }} {{pfrow| | | | |L| | | |Z| }} {{pfrow|T|T|T| |L|S|S|Z|Z| }} {{pfrow|J|T| | |S|S| |Z|O|O}} {{pfrow|J|J|J| |I|I|I|I|O|O}} {{pfend}} |} </div> 再证明跨行的 T2 也不行。<br> T-DPC 一手 T2 若要留下 2 的差值,就要做成[[跨行消除]],开火行需要先填 18 格。<br> 但是,即使前七块以最高效率占住开火行(如右图),也填不满 18 格,所以也肯定办不到。<br> (OSZ 占 6 格,I 占 4 格,TJ 占 6 格,L 为了构成 T3 式屋檐最多只能占 1 格,一共 17 格)</div> |} 由此可知,T-DPC 若想消四 PC,就必须丢弃“有 T2”的核心本质,退一步瞄向 S4PC,可考虑完全依赖最少方案。 [[Image:50-.png]] <big>'''最后,对于 J-DPC,高分方案就是 D4PC 专精方案'''</big> --> == 注释 == <references group="注"/> == 外链 == * [https://harddrop.com/wiki/DPC_Setups Hard Drop Wiki 基础 DPC 页面] * [https://harddrop.com/wiki/Extra_DPC_Setups Hard Drop Wiki 进阶 DPC 页面] * [https://docs.google.com/spreadsheets/d/1cjxVuqLVEyoBcGiHQyLU3k2EYQzbWLXWDy7rQpr4a2M/edit#gid=934185913 torchlight 的所有 DPC 的得分效率表] * [https://tetris.johnbeak.cz/dpc John Beak 的 DPC 数据库] * [https://docs.google.com/presentation/d/1pn09RCc2ZN25_wWkcQj7eaTlMW6Uow9bLThS9VJgAP0/edit#slide=id.p metallicLurker 的面向初学者最少 DPC 教学] * [https://www.youtube.com/watch?v=bG242y1XIjs&ab_channel=smolfeesh smolfeesh 的进阶 DPC 视频教学] [[Category:T 旋方法]] [[Category:全消方法]]
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